5m^2+140=55m

Solution for 5m^2+140=55m equation:

5m^2+140=55m

We move all terms to the left:

5m^2+140-(55m)=0

a = 5; b = -55; c = +140;
Δ = b2-4ac
Δ = -552-4·5·140
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-15}{2*5}=\frac{40}{10}
=4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+15}{2*5}=\frac{70}{10}
=7
$